x^2=18x+88

Solution for x^2=18x+88 equation:

x^2=18x+88

We move all terms to the left:

x^2-(18x+88)=0

We get rid of parentheses

x^2-18x-88=0

a = 1; b = -18; c = -88;
Δ = b2-4ac
Δ = -182-4·1·(-88)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-26}{2*1}=\frac{-8}{2}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+26}{2*1}=\frac{44}{2}
=22
$